2 réponses
- Le plus récent
- Le plus de votes
- La plupart des commentaires
3
You can convert bigint to date timestamp as below:
date_format(from_unixtime(bigint_timestamp_column/1000),’%Y-%m-%d %h:%i%p')
You can test this by running this sample:
select date_format(from_unixtime(1688183062393/1000), '%Y-%m-%d %h:%i:%s')
Here is how you'd query your table with condition:
select * from table_name where date_format(from_unixtime(1688183062393/1000), '%Y-%m-%d %h:%i:%s') > date_parse('2023-07-01', '%Y-%m-%d') and date_format(from_unixtime(1688183062393/1000), '%Y-%m-%d %h:%i:%s') < date_parse('2023-07-10', '%Y-%m-%d')
Hope you find this helpful.
Comment here if you have additional questions, happy to help.
Abhishek
0
Select DATE_FORMAT(timestamp,'%Y-%m-%d') where timestamp >= timestamp '2023-08-30' and timestamp <= timestamp '2023-09-01'
Thanks for your answer. This was one of my first tries and didn’t helped.
Contenus pertinents
- demandé il y a 2 ans
- demandé il y a 2 ans
- demandé il y a 2 ans
- AWS OFFICIELA mis à jour il y a 4 ans
- AWS OFFICIELA mis à jour il y a 8 mois
- AWS OFFICIELA mis à jour il y a 2 ans
Were you able to use this method in your use case, comment here if you have any additional questions?
Thanks for the answer. I tried this earlier and didn’t helped me . What I did is changed columns type and then looked for what I need in the table.