INVALID_FUNCTION_ARGUMENT: Invalid format: "13-12-2022" is malformed at "-12-2022"

Hi, I'm trying to convert a string into a date. The format from the string is 13-12-2022 (or for example 4-12-2022). I've used the follwing query:

, date_parse(Openingsdatum, '%d/%m/%Y')

In which Openingsdatum refers to the string colum of the dates. I figured out that the query uses tho format %m%d%y, so it switched. Could somebody explain why I'm getting this error?

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lisannegesch

질문됨 2년 전879회 조회

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수락된 답변

I believe you just need to replace the / with -.

I tried running the below statement with "13-12-2022" and "4-12-2022" . It works

select date_parse('4-12-2022', '%d-%m-%Y') as does_it_work

Ananth Tirumanur

답변함 2년 전

lisannegesch
2년 전
That would've been very easy but unfortunately I still got an error. A different one this time: SYNTAX_ERROR: line 25:3: Unexpected parameters (varchar, varchar(8)) for function date_format. Expected: date_format(timestamp with time zone, varchar(x)) , date_format(timestamp, varchar(x)) This query ran against the "db_retail_datascientists" database, unless qualified by the query. Please post the error message on our forum or contact customer support with Query Id: cd450b06-454d-4cb4-9719-b5a01e63e375
lisannegesch
2년 전
I'm sorry, wrong error haha. This is the error which I got. But I think I can fix this: INVALID_FUNCTION_ARGUMENT: Invalid format: ""

Thank you!

INVALID_FUNCTION_ARGUMENT: Invalid format: "13-12-2022" is malformed at "-12-2022"

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